Question

The perimeter of a triangle is 12p2 − 8p + 9 and two of its sides are 2p2 − 4p + 2 and 6p2 − 10p + 6. Find the third side.

Answer 1

Answer:

4p2 + 6p + 1

Step-by-step explanation:

12p2- 8p+ 9 - (2p2 - 4p +2 + 6p2- 10p + 6)

= 4p2 + 6p + 1

Hope this helps

Answer 2

Given: The perimeter of a triangle is$12p^{2} - 8p + 9$ and two of its sides are $2p^{2} - 4p + 2 \ and\ 6p^{2} - 10p + 6.$

We have to find the third side.

As we know that the perimeter of the triangle is calculated by a formula:

$P=a+b+c$

Where,

a = Side  

b = Base  

c = Side

We are solving in the following way:

Let assume the third side of the triangle be$x$.

We have,

The perimeter of a triangle is$12p^{2} - 8p + 9$ and two of its sides are $2p^{2} - 4p + 2 \ and\ 6p^{2} - 10p + 6.$

As we know,

$P=a+b+c$

$\Rightarrow 12p^{2} - 8p + 9=2p^{2} -4p + 2 +6p^{2} - 10p + 6+x\\\\\Rightarrow x= 12p^{2} - 8p + 9-2p^{2} +4p - 2 -6p^{2} + 10p - 6\\\\\Rightarrow x=4p^{2} +6p+1$

Solving the above equation further we get,

The third side of the triangle is$4p^{2} +6p+1$.

Hence, the third side of the triangle will be$4p^{2} +6p+1$.