Question

The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2: 3:4.
Construct the triangle.​

Answer 1

Answer:

Let the common multiple be x

∴ In ∆ABC, AB = 2x cm

, AC = 3x cm,

BC = 4x cm

Perimeter of triangle = 14.4 cm

∴ AB + BC + AC = 14.4

∴ 9x = 14.4

∴ x = 14.4/9

∴ x = 1.6

∴ AB = 2x = 2x 1.6 = 3.2 cm

∴ AC = 3x = 3 x 1.6 = 4.8 cm

∴ BC = 4x = 4 x 1.6 = 6.4

Hope it helps uh sister .....

Answer 2

Let the common multiple be x

∴ In ∆ABC, AB = 2x cm, AC = 3x cm, BC = 4x cm Perimeter of triangle = 14.4 cm

∴ AB + BC + AC = 14.4

∴ 9x = 14.4

∴ x = 14.4/9

∴ x = 1.6

∴ AB = 2x = 2x 1.6 = 3.2 cm

∴ AC = 3x = 3 x 1.6 = 4.8 cm

∴ BC = 4x = 4 x 1.6 = 6.4 cm

for diagram refer to the attachment