Question

The perimeter of a triangle is 144 m. If one of its sides is 48 m and the remaining (4)

two sides are in the ratio 3 : 5, find the area of the triangle.​

Answer 1

Answer:

Hi frnd hope my answer helps

Step-by-step explanation:

The perimeter of a triangular field is 144 m and the ratio of the sides is 3 : 4 : 5 The area of the field is

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ANSWER

Let the side of the triangle a,b and c be 3x,4x,5x

Perimeter =144 m

∴3x+4x+5x=144

⇒12x=144

⇒x=12

Thena=12×3=36m

b=4×12=48m

c=5×12=60

Then s=

2

a+b+c

=

2

36+48+60

=

2

144

=72

∴ Area of the triangle=

s(s−a)(s−b)(s−c)

⇒

72(72−36)(72−48)(72−60)

⇒

72×36×24×12

=864 m

2

Answer 2

Answer:

Perimeter of a triangle = side 1 +side 2+ side 3

Let, side 2and 3 be 3x and 5x respectively.

By the formula,

144=48+3x+5x

144-48=8x

96=8x

8x=96

x=96/8

x=12.

side 2 = 3x =3 into 12=36m.

side 3 = 5x = 5 into 12=60m.

Area of a triangle = 1/2bh

solve by formula area of triangle.