The perimeter of a triangle is 14a-3b +12c.if the two side of triangle are 4a+6b-8c and 3a-5b+11c respectively find the 3rd side
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two sides are given
4a+6b+8c+3a-5b+11c=14a-3b+12c
7a+b+19c=14a-3b+12c
14a-2b+12c-(7a+b+19c)
=7a-3a-7c
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4a+6b+8c+3a-5b+11c=14a-3b+12c
7a+b+19c=14a-3b+12c
14a-2b+12c-(7a+b+19c)
=7a-3a-7c
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