Question

the perimeter of a triangle is 16 a square minus 18 a + 8 and its two sides are 6a square - 100 and 8asquare + 24 find the third side​

Answer 1

Perimeter = sum of all sides

Now let the third side be x

So 16a^2 -18a + 8 = ( 6a^2 -100)+(8a^2+24) +x


16a^2 -18a + 8= 6a^2 -100 + 8a^2+24 +x


16a^2 -18a + 8= 14a^2 -76 +x

Now subtract 14a^2 from both sides

You will have ..
2a^2 -18a +8= x- 76

Now add 76 to both sides of the equation

You will have.....


2a^2 -18a +58 =x


So the third side should be 2a^2 -18a +58 =x


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