Question

The perimeter of a triangle is 240m and two of its sides measure

50m and 112m. Find the area of the triangle and the length of

the perpendicular on the side 112m from the opposite vertex. Pls explain in detail.

Answer 1

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Hope you will be able to understand
I have attached a copy of the solution

Answer 2

Step-by-step explanation:

perimeter of triangle = sum of all sides

240= 50+112+AB

240=162+AB

AB=240-162

third side=AB=78m

Area=√s(s-a)(s-b)(s-c)

s=a+b+c/2

s=50+112+78/2

s=240/2

s=120

Area=√s(s-a)(s-b)(s-c)

√120(120-50)(120-112)(120-78)

area=√2²×2²×2²×2²×3²×5²×7²

area=1680m²

By the problem

take 112m side as base

area of triangle=1/2×base×height

1680=1/2×112×BD

BD=1680/56

BD=30CM

Length of perpendicular(height)=30m