Math, asked by jitendrakumarkaushal, 3 days ago

The perimeter of a triangle is 25 cm. If the longest side is double the shortest side and the third Side is 5 more than the shortest side, find the sides of the triangle.​

Answers

Answered by GauthMathSolvid004
1

let the shortest side be x cm.

so longest side = 2x

third side = x+5 cm

so, perimeter = x + 2x + x+5

4x + 5 = 25

so, 4x = 25 - 5 = 20

so, x = 20/4 = 5

Hence, shortest side = x = 5 cm

longest side = 2x = 10 cm

third side = x+5 = 5+5 = 10 cm

Answered by GauthMath.

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