The perimeter of a triangle is 288m and the ratio of the sides is 3:4:5.Find the area of the triangle.
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Answers
Step-by-step explanation:
perimeter of a triangle = sum of all sides
288=3x+4x+5x
288=12x
X= 24
the dimensions are 72,96,120
area of a triangle=base × height ÷ 2
= 72.96/2= 3456m^2
Answer :-
Area of triangle is 3456 m²
The perimeter of the triangle is 288 m (given).
We know that,
A triangle contains three sides. And in question, we also gave its sides in the ratio 3:4:5.
Let the -
- the first side of the triangle be 3x
- the second side of the triangle be 4x
- the third side of the triangle be 5x
So,
Sum of it's (triangle) sides = 3x + 4x + 5x
According to question,
The perimeter of triangle = Sum of all sides of the triangle
Substitute the known values above to find the area of a triangle.
⇒ 288 = 3x + 4x + 5x
⇒ 288 = 12x
⇒ 288/12 = x
⇒ 24 = x
⇒ x = 24
First side of triangle = 3(24)
⇒ 72
Second side of triangle = 4(24)
⇒ 96
Third side of triangle = 5(24)
⇒ 120
Now,
Let the -
- base (B) of triangle be 72 m
- height or perpendicular (P) of triangle be 96 m
- hypoteneous (H) of triangle be 120 m
By Pythagoras theorem
→ (H)² = (B)² + (P)²
→ (120)² = (72)² + (96)²
→ 14400 = 5184 + 9216
→ 14400 = 14400
So,
⇒ 1/2 × 72 × 96
⇒ 72 × 48
⇒ 3456 m²