Question

The perimeter of a triangle is 300 m. If its sides are in the ratio 3:5:7. Find the area of the
triangle.​

Answer 1

Answer:

Please mark BRAINLIEST....

Answer 2

Answer :-

• The area of triangle is 2598.076m² or 1500√3m²

Step-by-step explanation:

To Find:-

• The area of triangle

Solution:

Given that,

• The perimeter of ∆ = 300m
• The ratio of the three sides = 3:5:7

∴ The sides of triangle :-

Assumption:

• Let us assume the sides of triangle as 3x, 5x and 7x.

We know,

Perimeter of ∆ = Sum of three sides,

⇒ 3x + 5x + 7x = 300

⇒ 8x + 7x = 300

⇒ 15x = 300

⇒ x = 300/15

⇒ x = 20

The sides are :-

• 3x = 3*20 = 60m
• 5x = 5*20 = 100m
• 7x = 7*20 = 140m.

According the question,

• The area of triangle :-

[ heron's formula ]

We know,

Semi-perimeter = ( a + b + c )/2

Where,

• a, b and c are the sides of triangle.

⇒ ( 60 + 100 + 140 )/2

⇒ ( 160 + 140 )/2

⇒ 300/2

⇒ 150

Now, Area of triangle, We know,

Area of triangle = √ s ( s - a ) ( s - b ) ( s - c )

⇒ √ s ( s - a ) ( s - b ) ( s - c )

⇒ √ 150 ( 150 - 60 ) ( 150 - 100 ) ( 150 - 140 )

⇒ √ 150 ( 90 ) ( 50 ) ( 10 )

⇒ √ 150 × 90 × 50 × 10

⇒ √ 6750000

⇒ 2598.07m² or 1500√3m²