Question

The perimeter of a triangle is 36 cm.   if its sides are in the ratio 1:3:2,then the largest side is

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Answer 1

Given:

• Perimeter of triangle = 36 cm
• Ratio of their sides = 1:3:2

To find:

• Measure of largest side.

SoluTion:

Let the first side be x, second be 3x and 3rd be 2x.

We know that,

Perimeter of triangle = Sum of all sides

Also, it is given that perimeter of triangle is 36 cm.

$\longrightarrow$ x + 3x + 2x = 36

$\longrightarrow$ 6x = 36

$\longrightarrow$ x = $\dfrac{36}{6}$

$\longrightarrow$ x = 6 cm

$\rule{200}2$

1st side:

$\longrightarrow$ x = 6 cm

2nd side:

$\longrightarrow$ 3x

$\longrightarrow$ 3 × 6

$\longrightarrow$ 18 cm

3rd side:

$\longrightarrow$ 2x

$\longrightarrow$ 2 × 6

$\longrightarrow$ 12 cm

Hence, length of longest side will be 18 cm.

Answer 2

Answer:

⇢ 18 is the length of the longest side.

Step-by-step explanation:

Given:-

⇢ The perimeter of a triangle is 36 cm. sides are in the ratio 1:3:2.

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Find:-

⇢Find the longest side.

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As per the given question:-

⇢ Let us assume x1, x3, x2 as the ratio of the three sides. Sum of three sides {x1 + x2 + x3 = 36 cm}.

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Calculations:-

⇢ $\sf{x1 + x2 + x3 = 6x}$

⇢ $\sf{6x = 36 \: cm}$

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Divide '36' with '6x' to find the length of units of each side.

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⇢ $\sf{\dfrac{36}{6x}}$

⇢ ${\boxed{\sf{6}}}$

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Therefore, 6 is the value and multiplying it with the ratio of the sides we find the largest side.

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⇢ $\sf{6 \times 1 = 6}$

⇢ $\sf{6 \times 3 = 18}$

⇢ $\sf{6 \times 2 = 12}$

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Therefore, 18 is the length of the longest side.