Math, asked by PuneetSahu3288, 1 year ago

The perimeter of a triangle is 36cm. And its sides are in the ratio of 3:4:5. Find the area of the triangle.

Answers

Answered by abhi569
51
Let sides are 3 x , 4 x and 5 x ,



Given that perimeter of the triangle is 36 cm.

So, sum of all sides =36 cm



↪ 3 x + 4 x + 5 x = 3 6

↪ 1 2 x = 3 6

↪ x = 3






So,
Sides are 3 x = 3 × 3 = 9 cm
4 x = 4 × 3 = 12 cm
5 x = 5 × 3 = 15






As we can see that 3 , 4 and 5 are Pythagorean triplets.


Area of triangle = ( 3 x × 4 x ) / 2

Area of triangle = 6 x² cm²

Area of triangle = 6( 3 )³ cm²

Area of triangle = 162 cm²
.

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Answered by SmãrtyMohït
31
❤❤Here is your answer ✌ ✌

\huge\underline {\red {\bold {Answer}}}

Let sides are 3 x , 4 x and 5 x , 
Given that perimeter of the triangle is 36 cm. 
So, sum of all sides =36 cm

3 x + 4 x + 5 x = 3 6
1 2 x = 3 6
x = 3

So, 
Sides are 3 x = 3 × 3 = 9 cm
4 x = 4 × 3 = 12 cm
5 x = 5 × 3 = 15

As we can see that 3 , 4 and 5 are Pythagorean triplets. 


Area of triangle = ( 3 x × 4 x ) / 2

Area of triangle = 6 x² cm²

Area of triangle = 6( 3 )³ cm²

Area of triangle = 162 cm²
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