Question

The perimeter of a triangle is 42 cm the length og the smalledt side is 12
cm and the length of the longest side is 16 cm. find the length of the third side . find the area of the triangle
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

oncept:-

Heron's Formula and Perimeter.

Let's Do!

12 + 16 + x = 4212+16+x=42

28 + x = 4228+x=42

x = 42 - 28x=42−28

x = 14 \: cmx=14cm

Now,

s = \dfrac{a + b + c}{2}s=

2

a+b+c

= \dfrac{12 + 16 + 14}{2}=

2

12+16+14

= \dfrac{42}{2} = 21=

2

42

=21

Now,

area = \sqrt{s(s - a)(s - b)(s - c)}area=

s(s−a)(s−b)(s−c)

\sqrt{21(21 -12)(21 - 16)(21 - 14) }

21(21−12)(21−16)(21−14)

\sqrt{21 \times 9 \times 5 \times 7}

21×9×5×7

= \sqrt{6615}=

6615

= 81.33 \: {cm}^{2}=81.33cm

2