The perimeter of a triangle is 45 CM. The longest side exceed The shortest by 8 cm and the sum of the length of the longest and shortest sides is twice the length of the other side. Find the length of the sides. Give me answer by using s
Determinants.
Answers
Answer: Largest side = 19cm
Smallest side = 11cm
other side =15cm
Step-by-step explanation:
~Let the length of shortest side of the triangle is x cm, longest side be 8 cm + length of shortest side i.e. ( x + 8 ) cm
=> Shortest side = x cm
=>Longest side = ( x + 8 ) cm
Other or Remaining side = perimeter - length of shortest side - length if largest side
=>Remaining side = 45 - x - x - 8
=>Remaining side = ( 37 - 2x ) cm
Now, A.T.Q,
the sum of length of the largest side and length of the shortest is equal to the 2 times if remaining side, So,
Largest side+shortest side = 2(other side)
: x+(x+8)= 2(37-2x)
: x+x+8= 74-4x
: 2x+8 = 74-4x
: 2x+4x = 74-8
: 6x = 66
: x = 66/6
: x = 11 = Shortest side,
Then;
Smallest side = x cm = 1 1 cm
Largest side = ( x + 8 ) cm = ( 1 1 + 8 ) cm = 19 cm
Other side = ( 45 - 1 1 - 19 ) cm = ( 45 - 30 ) cm = 15 cm
Hope it Helps!
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