The perimeter of a triangle is 450 m and its sides are in the ratio 12:5:13 find the area of the triangle
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Answered by
5
Given:- Perimeter = 450 m
Ratio = 12:5:13
Such that:- area = 1/2*base*height
by Pythagorean triplet::--
base = 5 m
height = 12 m
area = 12*5/2
area = 30 sq m
Therefore:- the area is 30 sq m
Ratio = 12:5:13
Such that:- area = 1/2*base*height
by Pythagorean triplet::--
base = 5 m
height = 12 m
area = 12*5/2
area = 30 sq m
Therefore:- the area is 30 sq m
Answered by
14
Answer:
⇒ Area = 6750 m²
Step-by-step explanation:
It is given that two sides a, b, c of the triangle are in the ratio 13 : 12 : 5. i.e.,
a : b : c = 13 : 12 : 5
⇒a = 13x , b = 12x, c = 5x
Therefore,
⇒ 2s = 450 = 13x + 12x + 5x
⇒ 450 = 30x
⇒ x = 450/30 = 15
So, the sides of the triangle are:
a = 13 × 15 = 195 m
b = 12 × 15 = 180 m
c = 5 × 15 = 75 m
It is given that perimeter = 450
⇒ 2s = 450
⇒ s = 450/2 = 225
Hence,
⇒ Area = √s ( s - a ) ( s - b ) ( s - c )
⇒ Area = √225 ( 225 - 195 ) ( 225 - 180 ) ( 225 - 75 )
⇒ Area = √ 225 × 30 × 45 × 150
⇒ Area = √5² × 3² × 3 × 5 × 2 × 3² × 5 × 5² × 2 × 3
⇒ Area = 5 × 5² × 3² × 3 × 2
⇒ Area = 6750 m²
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