Question

The perimeter of a triangle is 48 cm and its sides 5.
are 14 cm, 19 cm and (x + 4) cm. Find the value of​

Answer 1

Given:

✰ The perimeter of a triangle = 48 cm

✰ Sides of a triangle are 14 cm, 19 cm and (x + 4) cm respectively.

To find:

✠ The value of x.

Solution:

Let's understand the concept here! We will use formula to calculate perimeter of a triangle. As we are already provided with perimeter of triangle and the sides. Thus, putting the values in the formula and forming an adequate equation and doing required calculations we can easily find out the value of x.

Triangle:

A triangle is an enclosed figure of three sides.

Perimeter:

The perimeter of a triangle is the sum of the lengths of its three sides. Thus,

✭ The perimeter of a triangle = a + b + c ✭

Where,

• a, b and c are the lengths of the sides of the triangle.

Here,

• a = 14 cm
• b = 19 cm
• c = (x + 4) cm

Putting the values in the formula,

➛ 48 = 14 + 19 + x + 4

➛ 48 = 33 + x + 4

➛ 48 = x + 37

➛ x = 48 - 37

➛ x = 11

∴ The value of x = 11 cm

_______________________________

Answer 2

Given :

The perimeter of traingle is 48 cm and its sides are 14 cm , 19 cm and (x + 4) cm.

$\: \: \:$

To find :

The value of x.

$\: \:$

Solution :

We know that,

Perimeter of traingle = a + b + c

$~$

a = 14 cm

a = 14 cmb = 19 cm

a = 14 cmb = 19 cmc = x + 4

$\: \: \:$

Putting the values

$: \implies \sf48 = 14 + 19 + (x + 4)$

$\: \:$

$: \implies \sf48 = 33 + x + 4$

$\: \:$

$: \implies \sf48 = x + 37$

$\: \:$

$\large{ \underline{ \boxed{ { \red {\tt{ x = 11cm}}}}}}$

$\: \:$

$\:$

${ \boxed {\color{blue}{ \rm{The \: value \: of \: x \: is \ 11cm}}}}$