Question

The perimeter of a triangle is 48 feet. If the second side is 3 more than twice the first side and the third side is 5 more than the first side, then what are the lengths of each side?​

Answer 1

Answer:

1st side= 10 feet, 2nd= 23 feet,3rd= 15 feet

Step-by-step explanation:

let the 1st side be x

2nd side = ( 2x+3)

3rd side = ( x+5)

x + (2x+3) + (x+5) = 48 feet

4x+8= 48

4x= 48 - 8

x = 40÷4

x= 10

1st side = x = 10

2nd side = 2x + 3= 23

3rd side = x+5 = 15

Answer 2

Answer:

Let take 1st side be x

2nd side be 2x + 3

3rd side be x + 5

x + 2x + 3 + x + 5 = 48

4x + 8 = 48

4x = 48 - 8

4x = 40

x = 40/4

x = 10

2x + 3 = 2(10) + 3 = 20 + 3 = 23 feet

x + 5 = 10 + 5 = 15 feet