the perimeter of a triangle is 49 CM if one side is 7 cm longer than the second and 5CM shorter than the third side find the measure of third side of the triangle
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Answer:
17,10,22
Step-by-step explanation:
let 1st ,2nd, 3rd sides of triangle be x,y,z respectively
given, perimeter of triangle is 49cm.
I.e, x+y+z=49.
given one side is 7cm longer than 2nd
I.e,x=y+7
x-7=y
given 1st side is 5cm shorter than 3rd
I.e, x=z-5
x+5=z
as x+y+z=49
x+x-7+x+5=49
3x=51
x=17
y=x-7=17-7=10
z=x+5=17+5=22
therefore, x,y,z are 17,10,22 respectively
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