the perimeter of a triangle is 49 CM. one side is 7cm longer than another side and 5cm shorter than the third side. find the sides
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Answered by
10
Let The side =x
Second side=x-7
Third Side=x+5
Perimeter=a+b+c=x+x-7+x+5
49=3x-2
51=3x
x=17m
a=17m
b=17-7=10m
c=17+5=22m
Second side=x-7
Third Side=x+5
Perimeter=a+b+c=x+x-7+x+5
49=3x-2
51=3x
x=17m
a=17m
b=17-7=10m
c=17+5=22m
tejaskumar574:
pls mark
Answered by
3
perimeter of triangle =49
sum of all sides=49
x+7+5=49
x+12=49
x=49-12
x=37
therefore the side is 37cm
sum of all sides=49
x+7+5=49
x+12=49
x=49-12
x=37
therefore the side is 37cm
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