The perimeter of a triangle is 49 cm. The one side is 7 cm longer than the
other and 5 cm shorter than the third. Find the length of each side of the triangle.
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Let 1st side =x
2nd side =x-7
Third side =x+5
Perimeter of triangle =49
A+B+C=49
(x) +(x-7)+(x+5)=49
3x-2=49
x=(49+2) ÷3
x=51÷3
x=17
1st=17
2nd=17-7=10
3rd=17+5=22
2nd side =x-7
Third side =x+5
Perimeter of triangle =49
A+B+C=49
(x) +(x-7)+(x+5)=49
3x-2=49
x=(49+2) ÷3
x=51÷3
x=17
1st=17
2nd=17-7=10
3rd=17+5=22
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