The perimeter of a triangle is 5-3x+7y and two of its sides are 2y+3x-2 and 3y-x+3. Find the third side of the triangle.
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Answer:
2y-5x+4
Step-by-step explanation:
let required side
5-3x+7y = 2y+3x-2+3y-x+3+k
5+2-3 = 2x+3x+5y-7y+k
4 = 5x-2y+k
2y-5x+4 = k
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