Question

the perimeter of a triangle is 50 cm. one side of the triangle is 4 cm longer than the smallest side and the third side is 6 cm less than twice the smallest side. find the area of the triangle.​

Answer 1

ANSWER:

Let smaller side = a           --------------- (i)

one side = a + 4                 --------------- (ii)

third side = 2a - 6              --------------- (iii)

On solving (i),(ii),(iii) we get

= a + a + 4 + 2a - 6 =50

= 4a - 2 = 50

a = 13

Substituting a value in (i),(ii),(iii)

smaller side = 13

one side = 17

third side = 20

Perimeter  = 20 + 17 + 13/2

 = 50/2

= 25

Area = s(s-a)(s-b)(s-c)^1/2

= (25(25-13)(25-17)(25-20))^1/2

 = 20(30)^1/2

 = 20 root 30