Question

The perimeter of a triangle is 50cm.One of the sides is 4cm longer than the smaller side and the third side is 6cm lesser than twice the smaller sides.Find the area.

Answer 1

Answer:

Perimeter of triangle = 50 cm

Let the length of the smaller side be x cm. 

Length of the second side = (x + 4) cm

Length of the third side = (2x-6) cm

Sum of lengths of triangle = Perimeter

x + (x + 4) + (2x-6) = 50

x + x + 4 + 2x - 6 = 50

x + x + 2x + 4 - 6 = 50

4x - 2 = 50

4x = 50 + 2

x = 52/4 = 13

x = 13

Length of the first side = x cm = 13 cm

Length of the second side = (x + 4) cm = (13 + 4) cm = 17 cm

Length of the third side = (2x - 6) cm = (2 * 13 - 6) cm = 20 cm

FINDING OUT THE AREA OF THE TRIANGLE USING HERON'S FORMULA

Let a = 13, b = 17, c = 20

I have just simplified the square root as it is a surd. 

∴   or 109.54451  is the area of the triangle. 

Step-by-step explanation:

Answer 2

Answer:

x+4+x +2x-6=50

4x-2=50

4x=50+2

4x=52

x=52/4=13 is the ans