Question

The perimeter of a triangle is 560 m and its sides are in the ratio 25:24:7.find the area of the triangle

Answer 1

a: b: c = 25: 24 : 7

since the perimeter is 560 m ,

a= 250
b= 240
c= 70

Clearly
${a}^{2} = {b}^{2} + {c}^{2}$
hence the triangle is right angled.

Area =
$\frac{1}{2} \times b \times h \\ = \frac{1}{2} \times 240 \times 70 \\ = 120 \times 70 \\ = 8400 {cm}^{2}$

Mark this answer as brainliest answer

Answer 2

➡HERE IS YOUR ANSWER⬇

Given that :

The sides are in the ration

25 : 24 : 7

Let, x be the common multiple.

Then, the sides of the triangle are 25x m, 24x m and 7x m.

Given that :

Perimeter = 560 m

=> 25x + 24x + 7x = 560

=> 56x = 560

=> x = 10

Therefore the sides of the triangle are 250 m, 240 m and 70 m.

We see that :

240² + 70² = 250²,

which shows that the given triangle right-angled.

Therefore, the area of the given triangle is

= (1/2)×(base×height)

= (1/2)×(7×240) m²

= 8400 m²

■] FORMULA :

For any right-angled triangle, if a be height, v be base and c be hypotenuse, then by Pythagorous theorem, we get

height² + base² = hypotenuse²

=> a² + b² = c²

⬆HOPE THIS HELPS YOU⬅