Question

the perimeter of a triangle is 56cm . two sides of a triangle are 18cm and 14cm . find the length of the third side.​

Answer 1

$\huge{ \rm{ \underbrace{ question}}}$

The perimeter of a triangle is 56cm . two sides of a triangle are 18cm and 14cm . find the length of the third side.

$\huge{ \rm{ \underline{ solution \: :-}}}$

$\large{ \rm{ \underline{ given \: :-}}}$

❒ First side = 18cm

❒ Second side = 14 cm

❒ Let the third side be x

$\large{ \rm{ \underline{ To \: find \: :-}}}$

$\large{ \rm{ ⟹}} \: 18 + 14 + x = 54$

$\large{ \rm{ ⟹}} \: x = 54 - 32 = 24cm$

$\large{ \rm{ ❒ \: 24 \: = third \: side}}$

$\large{ \mathcal{ mark \: brainliest}} \: { \star}$

Answer 2

Step-by-step explanation:

A=hbb

2

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forhb

hb=﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2

2b=﹣564+4·563·18+4·563·14﹣4·(56·18)2﹣12·562·18·14﹣4·(56·14)2+8·56·182·14+8·56·18·142

2·14

Hope it helps.