Question

The perimeter of a triangle is 5a-3b+8 and two of its sides are a-2b+1 and 3a-5b+2. Find the third side of the triangle.

Answer 1

Answer:

Step-by-step explanation:

Given.,

Perimeter of triangle=5a -3b+8

The two sides of triangle=

1)a-2b+1

2)3a-5b+2

Find,

The third side of triangle

Solution,

Th formula of triangle is =some of all side(a+b+c)

Therefore,

a-2b+1+(3a-5b+2)+(side c)=

5a-3b+8

Know solve this equation,

a-2b+1+3a-5b+2+(side c)

a+3a-2b-5b+1+2

4a-7b+3+(side c)=5a-3b+8

(Side c)=5a-3b+8-(4a-7b+3)

(Side c)=5a-3b+8-4a+7b-3

(Side c) = 5a-4a-3b+7b+8-3

(Side c)= a+4b+5

Hence,

Found,(side c)= a+4b+5

I hope you can understand and also helpful to you.

Thank you.