Question

The perimeter of a triangle is 5a² + 3a - 1 and two of its sides are 2a - 5 + 7a² and 3a² +4 - a.

Find the third side of the triangle.

Answer 1

Answer:

Let the third side be x

Alq,

5a2+ 3a - 1 = 2a + 5+7a2 + 3a2 +4a +x 5a2 + 3a -1 = 6a + 10 a2 +5+x

5a2 10a2 + 3a - 6a -1 -5 = x

-5a2 - 3a -6 = x

Answer 2

Step-by-step explanation:

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