Question

The perimeter of a triangle is 5a²+3a_1 two of it side are 2a+5+7a²and 3a²+4a find the third side

Answer 1

Answer:

Let the third side be x

Alq ,

5a2+ 3a - 1 = 2a + 5+7a2 + 3a2 +4a +x

5a2 + 3a -1 = 6a + 10 a2 +5+x

5a2 - 10a2 + 3a - 6a -1 -5 = x

-5a2 - 3a -6 = x