Question

The perimeter of a triangle is 5a2 – 5a + 2. If two of its sides are 7a2 – 3a + 5 and 1 – 4a2 + a, find the third side of the triangle.

Answer 1

Answer:

Let the third side be x

Alq ,

5a2 + 3a - 1 = 2a + 5 + 7a2 + 3a2 + 4a + x

5a2 + 3a -1 = 6a + 10 a2 + 5 + x

5a2 - 10a2 + 3a - 6a -1 -5 = x

-5a2 - 3a -6 =x

Answer 2

Answer:

Step-by-step explanation:

let third side be x

x+7a²-3a+5+1-4a²+a=5a²-5a+2

x+3a²-2a+6=5a²-5a+2

x=2a²-3a+4