Question

the perimeter of a triangle is 6+12a+7a2 and two of its sides are 3a2-3a+12 and 2a2-5a-1.Find the third side​

Answer 1

Answer: Length of the third side is 2a² +20a -5 units

Step-by-step explanation: two of the sides are

3a²- 3a + 12 and 2a²- 5a -1

So, adding these, we get

5a²-8a + 11

We know that

Perimeter =  ( 1st side + 2nd side + 3rd side)

So,

3rd side= Perimeter  -  sum of the first side and second side  

= 7a² + 12a + 6 -(5a² - 8a +11)

= 7a² - 5a² + 12a + 8a +6 -11

= 2a² + 20a -5

Answer 2

Answer:

Step-by-step explanation:

letting third side as'x'

6+12a+7a2= 3a2-3a+12+ 2a2-5a-1+x

transpose nd solve!!!