The perimeter of a triangle
is 6 p²-4p +9 and two of
its Sides are p²-2p+1 and a
3p²-5p+3. find the third
side ?
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1
Answer:
2p^2+3p+5
Step-by-step explanation:
p^2-2p+1+3p^2-5p+3+A [let the third side be A] =6p^2-4p+9
A=6p^2-4p+9-(p^2-2p+1+3p^2-5p+3)
A=6p^2-4p+9-(4p^2-7p+4)
A=6p^2-4p+9-4p^2+7p-4
A=2p^2+3p+5
Therefore, the given is the value of the third side.
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