The Perimeter of a Triangle is 60 cm. It's Hypotenuse is 26 cm,Find the other Two sides and the area of the Triangle.......
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Let the two sides of the triangle be b and h.
Given that perimeter of a triangle = 60cm.
Given that hypotenuse = 26cm.
b + h + 26 = 60
b + h = 60 - 26
b + h = 34.
We know that In a right-angled triangle c^2 = a^2 + b^2
b^2 + h^2 = 676
b^2 + (34 - b)^2 = 676
b^2 + 1156 - 68b + b^2 = 676
2b^2 - 68b + 1156 = 676
2b^2 - 68b + 480 = 0
b^2 - 34b + 240 = 0
b^2 - 24b - 10b + 240 = 0
b(b - 24) - 10(b - 24) = 0
b = 24, 10.
Then h = 34 - b
= 34 - 24
= 10.
h = 34 - b
= 34 - 10
= 24
Therefore the sides of a triangle = 24 and 10.
Now,
Area of triangle = 1/2 * b * h
= 1/2 * 24 * 10
= 120cm^2.
Therefore the area of triangle = 120cm^2.
Hope this helps!
Given that perimeter of a triangle = 60cm.
Given that hypotenuse = 26cm.
b + h + 26 = 60
b + h = 60 - 26
b + h = 34.
We know that In a right-angled triangle c^2 = a^2 + b^2
b^2 + h^2 = 676
b^2 + (34 - b)^2 = 676
b^2 + 1156 - 68b + b^2 = 676
2b^2 - 68b + 1156 = 676
2b^2 - 68b + 480 = 0
b^2 - 34b + 240 = 0
b^2 - 24b - 10b + 240 = 0
b(b - 24) - 10(b - 24) = 0
b = 24, 10.
Then h = 34 - b
= 34 - 24
= 10.
h = 34 - b
= 34 - 10
= 24
Therefore the sides of a triangle = 24 and 10.
Now,
Area of triangle = 1/2 * b * h
= 1/2 * 24 * 10
= 120cm^2.
Therefore the area of triangle = 120cm^2.
Hope this helps!
siddhartharao77:
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