the perimeter of a triangle is 60cm n its hypotenuse is 25cm .Find other two sides?
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see friend i solved in a rather easy way
see there's something called pythagoreans triplet, it is (2m,m²-1,m²+1)
here 25 is m²+1
so m=√(25-1)=√24=2√6
therefore the other two numbers are
2m=2*2√6=4√6
m²-1=(2√6)²-1=24-1=23
you can check my answer by putting the formula b²+p²=h²
(2m)²+(m²-1)²=(m²+1)²
(4√6)²+(23)²=25²
96+529=625
625=625
LHS=RHS,hence proven
see there's something called pythagoreans triplet, it is (2m,m²-1,m²+1)
here 25 is m²+1
so m=√(25-1)=√24=2√6
therefore the other two numbers are
2m=2*2√6=4√6
m²-1=(2√6)²-1=24-1=23
you can check my answer by putting the formula b²+p²=h²
(2m)²+(m²-1)²=(m²+1)²
(4√6)²+(23)²=25²
96+529=625
625=625
LHS=RHS,hence proven
Assassin12:
please mark it the brainliest
thanks bro for u r answer......n also taking sone patience for me.......but the thing is u r answer is not equal to my standard........im little bit junior........but ill try to understand......... anyways thanks
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