The perimeter of a triangle is 60om and its
sides are in the ratio 3:4:5 What is its area?
Answers
Answer:
The area of triangle is 23100 m²
Step-by-step explanation:
According to the given ratios the ∆ ABc is a Scalene triangle
The ratios of the Scalene triangle ∆ ABC = 3:4:5
Let the ratios of Scalene triangle ∆ABC be 3x:4x:5x
Perimeter of the Scapene triangle ∆ ABC = 600 m
Perimetre = Sum of all the sides : The sum of terms of ratio of the Scalene triangle
600 m = 3x+4x+5x
600m = 12x
The sum of all the sides = 50 m
Semi perimeter of ∆ ABC = Total perimeter of triangle /2
Semi perimeter = 50 m / 2 = 25 m
Area of ∆ABC = √ 25*[ (25-3) (25-4) (25-5) ]
Area of ∆ABC = √25*[ ( 22*21*20) ]
So the area of triangle is 23100 m²
Answer:
150 cm^2
Step-by-step explanation:
let the sides of the triangle be 3x,4x and 5x.
the perimeter of the triangle is 60 cm.
ATQ,
3x + 4x + 5x = 60
12x = 60
x = 60/12 = 5
therefore, first side = 3x = 3 × 5 = 15 cm
second side = 4x = 4 × 5 = 20 cm
third side = 5x = 5 × 5 = 25 cm
semi perimeter,s = 60/2 = 30 cm
s - a = 30 - 15 = 15 cm
s - b = 30 - 20 = 10 cm
s - c = 30 - 25 = 5 cm
Area of the triangle = √30(30 - 15)(30 - 20)(30 - 25)
= √30 × 15 × 10 × 5
= √2×3×5×3×5×2×5×5
= 2×3×5×5 = 150 cm^2