Question

The perimeter of a triangle is 6a + 5b -2c. If two sides are a-b +6c and 3+a+6b - 10c, find the three sides ?​

Answer 1

Answer:

Let the 3 rd side be BC

Now,

a-b+6c + 3+a+6b-10c+BC=6a+5b-2c

2a+5b-4c+3+BC = 6a+5b-2c

BC=6a-2a+5b-5b-2c+4c-3

BC=4a+2c-3

Hence 3rd side is 4a+2c-3.

Now,

By finding the value of a, b and c.

you can do.

thanks