The perimeter of a triangle is 6p² - 4p + 9 and the length of two to its adjacent side are p² - 2p + 1 and 3p² - 5p + 3. Find the length if the third side of triangle. If p= 3, find the perimeter of the triangle.
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The perimeter of a triangle is 6p² - 4p + 9 and the length of two to its adjacent side are p² - 2p + 1 and 3p² - 5p + 3. Find the length if the third side of triangle. If p= 3, find the perimeter of the triangle.
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Perimeter of the triangle= Sum of the sides of the triangle
6p² - 4p + 9= p² - 2p + 1 + 3p² - 5p + 3 + 3rd side
3rd side= 6p² - 4p + 9 - [(p² - 2p + 1) + (3p² - 5p + 3)]
3rd side= 6p² - 4p + 9 - (4p² - 7p + 4)
3rd side= 2p² + 3p + 5
The 3rd side of the triangle has lenght is 2p² + 3p + 5.
Given,
p= 3
The perimeter of the triangle is 6p² - 4p + 9.
On substituting the values we get:
= 6 × 3² - 4 × 3 + 9
= 54 - 12 + 9
= 51
The perimeter of the triangle is 51 units.
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