Question

The perimeter of a triangle is 6p2-4p +9 and two of its sides are p2-2p+1 and
3p2-5p+3.
Find the third side of the triangle.
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Answer 1

Answer:

Given perimeter of triangle is 6p2−4p+9 and two of its sides are p2−2p+1 and 3p2−5p+3.

Let thee third side be c.

we k.n.t perimeter of a triangle p with sides a,b,c is p=a+b+c.

p= 6p2−4p+9

a= p2−2p+1 

b= 3p2−5p+3.

p=a+b+c

c=p−a−b

c=(6p2−4p+9)-(p2−2p+1)-(3p2−5p+3)

c=(6−1−3)p2+(−4+2+5)p+(9−1−3)

∴c=2p2+3p+5

∴ third side of given triangle is 2p2+3p+5.