Question

the perimeter of a triangle is 6x²-4x+9 and two of its sides are x²-2x+1 and 3x²-5x+3. find the third side of the triangle.

24x²+3x+5
8x²+3x+5
2x²+3x+5
20x²+3x+5​

Answer 1

Step-by-step explanation:

Let the third side be a.a.

perimeter = sum of sides

x²-2x+1+3x²-5x+3+a = 6x²-4x +9

x²+3x²-6x²-2x-5x+4x+1+9+a = 0

-2x²-3x+10+a = 0

2x²+3x-10-a = 0

a = 2x²+3x-10

Therefore the third side is 2x²+3x-10

Answer 2

Answer:

2x²+3x+5

Hope it helps and plz mark as Brainliest