The perimeter of a triangle is 70 inches. If side A is twice the length of side B, which is half the length of side C, the length of side C is __________ .
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Answer:
70=A+B+C (1)
since A=2B
and B=C/2
therefore 1 becomes:
70=2(C/2)+C/2+C
70=C+C/2+C = 5C/2
140=5C
C=28
Step-by-step explanation:
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