Question

The perimeter of a triangle is 74 inches. The length of the first side is twice the length of the second side. The third side is 4 inches more than the first side . Find the length of each side of a triangle

Answer 1

Answer:

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Let the first side be x.

ACCORDING to above question

The first side is 2 inches more than twice the second side:

First side = 2x+2

and the third side is 4 inches more than the first side:

Third side = x+4

The perimeter is the sum of the lengths of all sides, and we get

x+4+2x+2+x = 74

4x+6= 74

Add 4 both sides

6x = 78 Divide both sides by 4:

x = 13 is the first side

Second side 2(13)+2=28inches

Third side 3(13)-6=33 inches

All sides of triangle are :

28 inches, 33 inches,13inches

Answer 2

Answer:-

Given:

Perimeter of a triangle = 74 inches.

Let the length of the first side be x inches.

Hence,

• 2 * Length of the second side = x inches

→ Length of the second side = (x/2) inches

• Length of the third side = (x + 4) inches.

We know that,

Perimeter of a triangle = Sum of its three sides.

Hence,

→ 74 = x + x/2 + x + 4

→ 74 = (2x + x + 2x + 8)/2

→ 74 * 2 = 5x + 8

→ 148 - 8 = 5x

→ 140/5 = x

→ x = 28

Therefore,

• Length of first side = x = 28 inches.

• Length of second side = x/2 = 28/2 = 14 inches.

• Length of third side = x + 4 = 28 + 4 = 32 inches.

Verification:-

Sum of the three sides = 74 inches

→ 28 + 14 + 32 = 74

→ 74 = 74

Hence, verified.