Question

The perimeter of a triangle is 7p^2 -8p+9 and two of its sides are 2p^2 -p + 1 and 11p^2 -3p + 5.find the third side of the triangle

Answer 1

Step-by-step explanation:

परिमाप = 7p² - 8p + 9

(2p²-p+1)+(11p²-3p+5) + x = 7p²-8p+9

13p² - 4p + 6 + x = 7p² - 8p + 9

6p² + 4p - 3 + x = 0

x = - 6p² - 4p + 3

x = -(6p²+4p -3)

Answer 2

Answer:

-6p²-4p+3

Step-by-step explanation:

perimeter of a triangle =7p²-8p+9

the two sides of a triangle =2p²-p+1 and 11p²-3p+5

the third side =x

Then,

(2p²-p+1) + (11p²-3p+5)+x=7p²-8p+9

2p²-p+1+11p²-3p+5+x=7p²-8p+9

13p²-4p+6+x=7p²-8p+9

13p²-7p²-4p+8p+x+6-9=0

6p²+4p-3+x

x=-6p²-4p+3