Question

the perimeter of a triangle is 7p²-5p+11 and two side of its side are p²+2p-1 and 3p²-6p+3 find the third side of the triangle​

Answer 1

Answer:

The third side is 3p²- p - 9

Step-by-step explanation:

Given,

Perimeter of triangle = 7p²-5p+11

One of the side = p²+2p-1

Another side = 3p²-6p+3

Let the third side be y

so,

Perimeter = Sum of three sides

= 7p²-5p+11 = p²+2p-1 + 3p²-6p+3 + (y)

(Keeping y in RHS and moving all other terms to LHS)

= 7p²-5p+11 -p²-2p+1 - 3p²+6p-3 =y

= 3p²-p-9=y

= y=  3p²- p - 9

Hope You got it :-))

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Answer 2

third side is 3p^2 - p - 9