Question

the perimeter of a triangle is 7x-10 one of the sides is x-6 and another is 3x+2.find the third side

Answer 1

let the other side be N

perimeter of the triangle

= x-6 + 3x + 2 + N

now

x-6 + 3x + 2 + N = 7x -10

4x - 4 + N = 7x - 10

N = 3x - 6

the third side = 3x - 6

Answer 2

I hope this answer is right