The perimeter of a triangle is 7x^2 - 17xy + 15y^2+ 8 and two sides are 3x^2 - 6xy + 4y^2 - 5 and 2x^2 9xy +672 +6. Find the third side of the triangle
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Answer:7x^2-17xy+5y^2+8 = (4x^2-7xy+4y^2-3 )+ ( 6y^2-8xy+x^2)+ thirdside
2x^2-2xy-5y^2+11 = thirdside
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Step-by-step explanation:
7x^2-17xy+5y^2+8 = (4x^2-7xy+4y^2-3 )+ ( 6y^2-8xy+x^2)+ thirdside
2x^2-2xy-5y^2+11 = thirdside
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