Question

the perimeter of a triangle is 7x^2-17xy+​

Answer 1

Check the above attachment

Answer 2

let third side be k

perimeter of triangle = sum of all sides

7x^2 - 17xy + 5y^2 + 8 =

(4x^2 +7xy + 4y^2 -3) + k +(x^2-8xy+6y^2+5)

7x^2-17xy+5y^2+8 = 5x^2-xy+10y^2+2+k

k = 7x^2-5x^2-17xy+xy+5y^2-10y^2+8-2

k = 2x^2-16xy-5y^2+6