the perimeter of a triangle is 7x²-17xy+15y²+8 and two sides are 3x²-6xy+4y²-5 and 2x²-9xy + 6y²+6 find the third side of triangle
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Answer:
third side = 2x² - 2xy + 5y² + 7
Step-by-step explanation:
add the two sides of triangle
= (3x² - 6xy + 4y² - 5) + (2x² - 9xy + 6y² + 6)
= 5x² - 15xy + 10 y² + 1
subtract the sum of two sides from the perimeter
= ( 7x² - 17xy + 15y² + 8 ) - ( 5x² - 15xy + 10y² + 1 )
= 7x² -17xy +15y² + 8 - 5x² + 15xy - 10 y² - 1
= 2x² -2xy + 5y² + 7
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