Question

The perimeter of a triangle is 7x2 + x – 1. The two sides of triangle are x + 3 and 5x2 + 1. Find the third side

Answer 1

perimeter of triangle = a + b + c

where a ,b ,c are side of triangle

a = 5x + 56

b = -16 x^2 -3x -5

perimeter = 7 x^2 + 7x - 7

7 * x^2 +7*x -7 = 5x + 56 + ( -16 x^2 -3x -5 ) + c

c = 7*x^2 +16*x^2 +7x -5x +3x -7 -56 +5

c = 23*x^2 + 5x -58

third side = 23*x^2 +5x -58

Hope it's helpful dear.............

Answer 2

Answer:

1. x+3+5x2+1+a=7x2+x-1
2. a=7x2+x-1-x-3-5x2-1
3. a=2x2-5