Question

The perimeter of a triangle is 8+13a+7a2 and two of its sides are 2a2 +3a+ 2 and 3a2 – 4a-1.

Find the third side of the triangle.​

Answer 1

Step-by-step explanation:

The perimeter of a triangle is 8+13a+7a2

two of its sides are 2a2 +3a+ 2 and 3a2 – 4a-1.

Two sides of triangle are given, let the non given side be x

Perimeter of triangle = sum of all sides

(2a2 +3a+ 2) + (3a2 – 4a-1) + x = 8+13a+7a2

(4a +3a + 2) +(6a - 4a - 1) + x =8+13a+14a

x = 7 + 18a

Third side of triangle is 7 + 18a