Question

The perimeter of a triangle is 8a^2

– 3a – 4 and two of its sides are 3a^2

– 5a – 5 and

2a^2

– a – 3​

Answer 1

Step-by-step explanation:

Two sides of triangle are 2a

2

+3a+2 and 3a

2

−4a−1

Let the third side be s

Perimeter=8+13a+7a

2

=2a

2

+3a+2+3a

2

−4a−1+s

⟹s=2a

2

+15a+7

So, the third side of triangle is =2a

2

+15a+7