Question

The perimeter of a triangle is 8x+13a+7a. And two of its sides 2a+3a+2 and 3a-4a-1 find the third angle

Answer 1

equation of perimeter of a triangle is a + b + c

let the 3rd side be 'x'

=

(2a + 3a + 2) + (3a - 4a - 1) + x = (8x + 13a + 7a)

2a + 3a + 3a - 4a + 2 - 1    +   x   = (8x + 13a + 7a)

4a + 1 + x = 8x + 13a + 7a

x = 8x + 13a + 7a - 4a + 1

x = 8x + 16a + 1

the 3rd side is  (8x + 16a + 1)

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