The perimeter of a triangle is 9 x square - 3 x 3 x + 1 and 2 of its sides areThe perimeter of a triangle is 9 x square - 3 x 3 x + 1 and 2 of its sides are 2 X square + 6 x minus 4 and 9 x square - 11 + 1 find the third side
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Answer:
THE THIRD SIDE, side c = 17-15x-2x².
Step-by-step explanation:
let the triangle be TRIANGLE ABC
THEREFORE, perimeter given=9x²-3(3x+1)= 9x²-9x+3
given, two sides of the triangle are
- 2x²+6x-4, and ( let this side be side a )
- 9x²-11+1 = 9x²-10 ( let this side be side b )
- let the remaining side be side c.
a+b = 2x²+6x-4 + 9x²-10 = 11x²+6x-14
perimeter of triangle = sum of all sides
therefore, c = 9x²-9x+3-( 11x²+6x-14)
c = 9x²-11x²-9x-6x+3+14
c = -2x²-15x+17
c = 17-15x-2x².
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